这是一门ICSI 311的编程代写网课代上，介绍编程语言的设计和实现，包括语言特性、范式和设计决策。 简要介绍功能和逻辑编程范式并强化面向对象的概念。 讨论解释器、编译器、transpires 和虚拟机，包括词法分析、解析、语义分析、优化、代码生成。 自动机和状态机简介。 先决条件：ICSI/ICEN 210 和 I CSI/I CEN 213 要求 C 级或更高。 CoursePear IT作业代写 @2009。
This assignment is extremely important – (nearly) every assignment after this one uses this one!
If you have bugs or missing features in this, you will need to fix them before you can continue on to new assignments. This is very typical in software development outside of school.
You must submit .java files. Any other file type will be ignored. Especially “.class” files.
You must not zip or otherwise compress your assignment. Blackboard will allow you to submit multiple files.
You must submit buildable .java files for credit.
This assignment must have six new source files (Parser.java, Node.java, IntegerNode.java, FloatNode.java, MathOpNode.java, Interpreter.java) as well as your first three source files (Shank.java, Token.java, Lexer.java).
The parser will take the collection of tokens from the lexer and build them into a tree of AST nodes. To start this process, make an abstract Node class. Add an abstract ToString override. Now create an IntegerNode class that derives from Node. It must hold an integer number in a private member and have a read-only accessor. Create a similar class for floating point numbers called FloatNode.java. Both of these classes should have appropriate constructors and ToString() overrides.
Create a new class called MathOpNode that also derives from Node. MathOpNode must have an enum indicating which math operation (add, subtract, multiply, divide) the class represents. The enum must be read-only. The class must have two references (left and right) to the Nodes that will represent the operands. These references must also be read-only and an appropriate constructor and ToString() must be created.
Reading all of this, you might think that we can just transform the tokens into these nodes. This would work, to some degree, but the order of operations would be incorrect. Consider 3 * 5 + 2. The tokens would be NUMBER TIMES NUMBER PLUS NUMBER. That would give us MathNode(*,3,MathNode(+,5,2)) which would yield 21, not 17.
Create a Parser class (does not derive from anything). It must have a constructor that accepts your collection of Tokens. Create a public parse method (no parameters, returns “Node”). Parse must call expression (it will do more later) and then matchAndRemove() a newLine. You must create some helper methods as matchAndRemove() as described in lecture.
The classic grammar for mathematical expressions (to handle order of operations) looks like this:
EXPRESSION = TERM { (plus or minus) TERM}
TERM = FACTOR { (times or divide) FACTOR}
FACTOR = {-} number or lparen EXPRESSION rparen
Turn each of these (expression, term, factor) into a method of Parser. Use matchAndRemove to test for the presence of a token. Each of these methods should return a class derived from Node. Factor will return a FloatNode (NUMBER with a decimal point) or an IntegerNode (NUMBER without a decimal point) OR the return value from the EXPRESSION. Note the unary minus in factor – that is important to bind the negative sign more tightly than the minus operation. Also note that the curly braces are “0 or more times”. Think about how 3*4*5 should be processed with these rules. Hint – use recursion and a helper method. Also think carefully about how to process “number”, since we have two different possible nodes (FloatNode or IntegerNode). Depending on how you implemented your lexer, factor may or may not need to deal with negating the number.
Finally, we will build (the beginning of) our interpreter. Create a new class called Interpreter. Add a method called “Resolve”. It will take a Node as a parameter and return a float. For now, we will do all math as floating point. The parser handles the order of operations, so this function is very simple. It should check to see what type the Node is:
For FloatNode, return the value.
For IntNode, return the value, cast as float.
For MathOpNode, it should call Resolve() on the left and right sides. That will give you two floats. Then look at the operation (plus, minus, times, divide) and perform the math.
Make sure that you test your code. Change your main to instantiate a parser (passing in the tokens from the lexer) and then call parse on the parser. Right now, it will only process a single line. Print your AST by using the “ToString” that you created. Use several different mathematical expressions and be sure that order of operations is respected. Then add a call to Resolve() and check the math.
Rubric | Poor | OK | Good | Great |
| Comments | None/Excessive (0) | “What” not “Why”, few (5) | Some “what” comments or missing some (7) | Anything not obvious has reasoning (10) |
| Variable/Function naming | Single letters everywhere (0) | Lots of abbreviations (5) | Full words most of the time (8) | Full words, descriptive (10) |
| Create the AST classes | None (0) | Classes missing (5) | All classes present, some methods missing (10) | All classes and methods (15) |
| Parser class | None (0) | Constructor or private member (5) | Constructor and private member (10) | |
| Helper Method(s) | None(0) | At least 1 (5) | ||
| Factor Method | None (0) | Significantly Attempted (10) | Correct (15) | |
| Expression Method | None (0) | Significantly Attempted (10) | Correct (15) | |
| Term Method | None (0) | Significantly Attempted (10) | Correct (15) | |
| Resolve Method | None (0) | Correct(5) |
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